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a^2-2a+0.4=0
a = 1; b = -2; c = +0.4;
Δ = b2-4ac
Δ = -22-4·1·0.4
Δ = 2.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{2.4}}{2*1}=\frac{2-\sqrt{2.4}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{2.4}}{2*1}=\frac{2+\sqrt{2.4}}{2} $
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